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4 votes
Is
a^2(a-0.4)^3 completely factored?

The original question was to completely factor this:

a^5-0.064a^2

User Tedsuo
by
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1 Answer

6 votes

Answer:


\bf a^2* (a - 0.4)(a^2 + 0.4a + 0.16)

Explanation:

Factorize:

First take out the common term a².


a^5 - 0.064a^2= a^2*(a^3 - 0.064)\\\\

Now, factorize using the identity a³ - b³

a³ - b³ = (a - b) (a² + ab + b²)


a^2 * (a^2 - 0.064) = a^2 * (a^3 - 0.4^3)


= a^2 * (a - 0.4) * (a^2 + a*0.4 + 0.4^2)\\\\=a^2 * (a - 0.4)(a^2 + 0.4a + 0.16)

User Frederick Ollinger
by
7.8k points

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