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A group of people were asked if they had run a red light in the last year. 131 responded "yes", and 452 responded "no". Find the probability that if a person is chosen at random, they have run a red light in the last year. Give your answer as a fraction or decimal accurate to at least 3 decimal places Submit QuestionQuestion 9

User Brian Vo
by
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2 Answers

3 votes

Answer:

131/583

Explanation:

Probability is the measure of likelihood or chance that an event will occur.


\text{Probability} = \frac{\text{Possible outcome of event}}{\text{Total outcome}}

Total number of people asked if they had run a red light = number of people that responded 'yes' + number of people that responded 'no'


\text{Total outcome} = 131+452


\text{Total outcome} = 583


\text{Possible outcome} = \ \text{number of people that responded yes} = 131

Probability that if a person is chosen at chosen at random, they have run a red light in the last year will be 131/583.

User Kschaeffler
by
8.2k points
7 votes

Answer:

.224 or 224/1000 or 28/125

Explanation:

The probability of a person chosen at random having run a red light in the last year is:

P(run a red light) = Number of people who said "yes" / Total number of people surveyed

P(run a red light) = 131 / (131 + 452)

P(run a red light) ≈ 0.224 (rounded to 3 decimal places)

So the probability is approximately 0.224 or 224/1000 or 28/125.

User Joe Bobby
by
8.7k points

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