Question

125 cm cube of 0.100 mol/ dm cube of copper (II) sulfate solution is required to react completely with a solution containing 25 cm cube of sodium hydroxide. Calculate the concentration of sodium hydroxide in mol/ dm cube

Answer 1

Step-by-step explanation:

The balanced chemical equation for the reaction between copper (II) sulfate and sodium hydroxide is:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

We can use the mole ratio of CuSO4 to NaOH to find the number of moles of NaOH required to react with 0.100 moles/dm3 of CuSO4:

1 mole CuSO4 reacts with 2 moles NaOH

0.100 moles/dm3 CuSO4 will react with 0.200 moles/dm3 NaOH

Now we can use the volume and number of moles of NaOH to calculate its concentration:

25 cm3 = 0.025 dm3

Concentration of NaOH = number of moles / volume

Concentration of NaOH = 0.200 moles/dm3 / 0.025 dm3

Concentration of NaOH = 8.00 mol/dm3

Therefore, the concentration of sodium hydroxide in the solution is 8.00 mol/dm3.