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(a) Factorise 25t²₋ 4
(b) Factorise x²₋6x₋3xy₊18y

User Degath
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2 Answers

3 votes

(a)

.

in this case, a= 25t and b= 4.

.

ans: (5t-4)(5t+4)

User Bnrdo
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1 vote

Explanation:

(a) To factorize 25t² - 4, we can use the difference of squares formula:

a² - b² = (a + b)(a - b)

In this case, a = 5t and b = 2. So we have:

25t² - 4 = (5t + 2)(5t - 2)

Therefore, 25t² - 4 can be factorized as (5t + 2)(5t - 2).

(b) To factorize x² - 6x - 3xy + 18y, we can group the terms:

(x² - 3xy) - (6x - 18y)

We can then factor out the common factors from each group:

x(x - 3y) - 6(x - 3y)

Notice that both terms have a factor of (x - 3y), so we can factor it out:

(x - 3y)(x - 6)

Therefore, x² - 6x - 3xy + 18y can be factorized as (x - 3y)(x - 6).

User Yemerra
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