Question

Calculate the kinetic energy of a bullet of mass 0.015 kg, traveling at a speed of 240 m/s.

Answer 1

The kinetic energy (KE) of an object is given by the formula:

KE = (1/2) * m * v^2

where m is the mass of the object and v is its velocity.

Substituting the given values, we get:

KE = (1/2) * 0.015 kg * (240 m/s)^2

Simplifying, we have:

KE = 0.5 * 0.015 kg * 57600 m^2/s^2

KE = 432 J

Therefore, the kinetic energy of the bullet is 432 Joules.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

The kinetic energy of an object is given by the formula:

KE = 1/2 * m * v^2

where m is the mass of the object and v is its velocity.

Plugging in the given values, we get:

KE = 1/2 * 0.015 kg * (240 m/s)^2

= 1/2 * 0.015 kg * 57600 m^2/s^2

= 432 J

Therefore, the kinetic energy of the bullet is 432 Joules.