Explanation:
(a) If the order of the choices is relevant, we can choose the first object in 5 ways, and the second object in 4 ways (since we cannot choose the same object again). Therefore, the total number of ways to choose 2 objects without replacement and with order being relevant is:
5 x 4 = 20 ways
(b) If the order of the choices is not relevant, we need to use the combination formula, which is:
nCk = n! / (k! * (n-k)!)
where n is the total number of objects, and k is the number of objects we want to choose.
In this case, we want to choose 2 objects out of 5, so n = 5 and k = 2. Therefore, the number of ways to choose 2 objects without replacement and with order not being relevant is:
5C2 = 5! / (2! * (5-2)!) = 10 ways
Therefore, there are 20 ways to choose 2 objects without replacement and with order being relevant, and 10 ways to choose 2 objects without replacement and with order not being relevant.