Answer:
Explanation:
Question 1
Part A:
To predict the number of times Harris will spin a sum less than 10, we need to find the probability of getting a sum less than 10 and multiply it by the total number of spins, which is 500.
The possible outcomes of the first spinner are 1, 2, and 3, and the possible outcomes of the second spinner are 4, 5, 6, 7, and 8. The minimum sum we can get is 1+4=5, and the maximum sum we can get is 3+8=11.
To get a sum less than 10, we can get:
1+4=5
1+5=6
1+6=7
1+7=8
1+8=9
2+4=6
2+5=7
2+6=8
2+7=9
3+4=7
3+5=8
3+6=9
There are 12 possible outcomes that result in a sum less than 10. So the probability of getting a sum less than 10 is 12/15, or 4/5.
To find the number of times Harris will spin a sum less than 10, we can use the equation:
probability of getting a sum less than 10 × total number of spins = x
So the equation that can be solved to predict the number of times Harris will spin a sum less than 10 is:
C) 12/15 = x/500
Part B:
To find the number of times Harris should expect to spin a sum that is 10 or greater, we can subtract the number of times he will spin a sum less than 10 from the total number of spins:
total number of spins - number of times he will spin a sum less than 10 = number of times he should expect to spin a sum that is 10 or greater
Substituting the values, we get:
500 - (12/15 × 500) = 500 - 400 = 100
So Harris should expect to spin a sum that is 10 or greater 100 times.