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C is 2 units closer to B than it is to A, if A = 5, B=15

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Answer:

the coordinate of C is 10.5, and the distance between A and C is 10.5 - 5 = 5.5, and the distance between B and C is 15 - 10.5 = 4.5.

Explanation:

If C is 2 units closer to B than it is to A, then we can find the distance between A and C and between B and C by using the distance formula:

Distance between two points (x1, y1) and (x2, y2) = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

Let x be the coordinate of C. Then, the distance between A and C is x - 5, and the distance between B and C is 15 - x. We know that the distance between B and C is 2 units greater than the distance between A and C, so we can set up an equation:

15 - x = 2 + (x - 5)

Simplifying and solving for x, we get:

15 - x = 2 + x - 5

18 - x = x - 3

2x = 21

x = 10.5

Therefore, the coordinate of C is 10.5, and the distance between A and C is 10.5 - 5 = 5.5, and the distance between B and C is 15 - 10.5 = 4.5.

User KiynL
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