Question

Problem C

Red roses are dominant to white roses and tall are dominant to short. Cross a flower that is homozygous red

and short with a flower that is white and heterozygous tall.

Parent Genotypes

Phenotypic Ratio:

Answer 1

Genotype: RRtt x rrTt, or in words, RED-RED-SHORT-SHORT x WHITE-WHITE-TALL-SHORT

Step-by-step explanation:

Let's start by defining everything.

Red = R

White = r

Tall = T

Short = t

The Prompt tells us that we have a Homozygous red first parent, which is short and red. As red is dominant and homozygous this means that colour traits will be RR for parent 1. We also know they are short, and if they are short, this means they will not have any tall genes since tall is dominant.

Thus, parent 1 is RRtt.

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Parent 2 is white and heterozygous tall. Let's start with the colour. Since it is white, and white traits are recessive (not dominant), this means that the white parent must be rr. In terms of height, we are given that the parent is heterozygous, which means they have both T and t. Thus,

Parent 2 genotype is rrTt.

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In terms of phenotype, you will have to do a dihybrid cross punnet square.

Cross: rrtT x RRtt

Rt Rt Rt Rt

rT RrTt RrTt RrTt RrTt

rT RrTt RrTt RrTt RrTt

rt Rrtt Rrtt Rrtt Rrtt

rt Rrtt Rrtt Rrtt Rrtt

Phenotype:

1/2 RrTt, which means red tall,

1/2 Rrtt, which means red short

Hope this helped!