Answer:
Explanation:
If the zeros and their multiplicities are given, we can write the polynomial as the product of linear factors corresponding to each zero.
For this problem, the polynomial has zeros of -9 (multiplicity 1) and -1 (multiplicity 2), so the linear factors are:
(x + 9) and (x + 1)^2
To find the third factor, we use the fact that the degree of the polynomial is 3. We can multiply the linear factors together and then simplify:
(x + 9)(x + 1)^2 = (x^2 + 10x + 9)(x + 1)
= x^3 + 11x^2 + 19x + 9
Therefore, the polynomial with zeros of -9 (multiplicity 1), -1 (multiplicity 2), and degree 3 is:
f(x) = x^3 + 11x^2 + 19x + 9