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A pipe with the diameter of 2.4 cm discharges water a rate 2.8 m per second. find the volume of water discharges one and a half hour, giving the answer in litres?

User Bkqc
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Answer: approximately 68,404 liters.

Explanation:

To solve the problem, we first need to find the cross-sectional area of the pipe, which we can calculate using the formula for the area of a circle:

A = πr^2

where r is the radius of the pipe, which is half the diameter. So, in this case, the radius is 2.4 cm / 2 = 1.2 cm.

A = π(1.2 cm)^2

A ≈ 4.5239 cm^2

Next, we can use the formula for volume flow rate to find the volume of water that is discharged per second:

Q = Av

where Q is the volume flow rate, A is the cross-sectional area of the pipe, and v is the velocity of the water. In this case, we have:

Q = (4.5239 cm^2)(2.8 m/s)

Q ≈ 0.01266 m^3/s

To find the volume of water discharged in one and a half hours (which is 5400 seconds), we can multiply the volume flow rate by the time:

V = Qt

V = (0.01266 m^3/s)(5400 s)

V ≈ 68.404 m^3

Finally, to convert the volume from cubic meters to liters, we can multiply by 1000:

V = 68.404 m^3 × 1000 L/m^3

V ≈ 68,404 L

Therefore, the volume of water discharged in one and a half hours is approximately 68,404 liters.

User Mhd
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