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A rectangular paperboard measuring 33 inches long and 24 inches wide has a semicircle cut out of it, as shown below. Find the area of the paperboard that remains. Use the value 3.14 , and do not round your answer. Be sure to include the correct unit in your answer.

User DizzyDoo
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1 Answer

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Answer: 565.92 square inches.

Explanation:

To find the area of the paperboard that remains, we need to subtract the area of the semicircle from the area of the rectangle.

The rectangle has a length of 33 inches and a width of 24 inches, so its area is:

A_rect = length x width

A_rect = 33 in x 24 in

A_rect = 792 sq in

To find the area of the semicircle, we need to first find its radius. The diameter of the semicircle is the same as the width of the rectangle, which is 24 inches. So, the radius is:

r = 1/2 x diameter

r = 1/2 x 24 in

r = 12 in

The area of the semicircle is:

A_semicircle = 1/2 x pi x r^2

A_semicircle = 1/2 x 3.14 x 12^2

A_semicircle = 1/2 x 3.14 x 144

A_semicircle = 226.08 sq in

To find the area of the paperboard that remains, we subtract the area of the semicircle from the area of the rectangle:

A_remaining = A_rect - A_semicircle

A_remaining = 792 sq in - 226.08 sq in

A_remaining = 565.92 sq in

Therefore, the area of the paperboard that remains is 565.92 square inches.

User AlfC
by
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