Question

Solve for x to the nearest tenth.
8
3
4
7

Answer 1

x=4.9

Explanation:

using the Pythagorean theorem to find the leg of tringle A:

`a^(2) +b^(2) =c^(2)`

`y^(2) +3^(2) =7^(2)`

`y^(2) +9=49\\y^(2) =40\\\sqrt{y^(2) } =√(40) \\y=√(40)`

we know that the hypotenuse for tringle B is
`√(40)` so, now we can find the value of x:

using the Pythagorean theorem:

`a^(2) +b^(2) =c^(2)`

`4^(2) +x^(2) =(√(40) )^(2)`

`16+x^(2) =40\\x^(2) =24\\\sqrt{x^(2) } =√(24) \\x=4.9`