Question

Express the following as the product of prime factors in exponential form
(a) 432 (b) 729×64

Answer 1

Below in bold.

Explanation:

2) 432

2) 216

2) 108

2) 54

3) 27

3) 9

3

So 432 = 2^4 * 3^3.

3)729

3)243

3)81

3)27

3)9

3

64 = 2^6

So the answer is 2^6 * 3^6

Answer 2

Answer: 729×64 is: (3^3 × 2^3)^2

Explanation:

(a) To express 432 as the product of prime factors in exponential form, we can follow these steps:

Divide by 2 as many times as possible until the result is odd: 432 ÷ 2 = 216 ÷ 2 = 108 ÷ 2 = 54 ÷ 2 = 27 (5 times)

Divide by 3 as many times as possible until the result is not divisible by 3: 27 ÷ 3 = 9 ÷ 3 = 3 (2 times)

Since 3 is a prime number, we cannot divide by any other prime number to obtain a smaller result. Therefore, the prime factorization of 432 is: 2^4 × 3^3.

(b) To express 729×64 as the product of prime factors in exponential form, we can follow these steps:

Rewrite each factor as a power of a prime: 729 = 3^6 and 64 = 2^6.

Multiply the powers of each prime together: (3^6) × (2^6) = 3^6 × 2^6.

Simplify the result by factoring out the highest possible power of each prime: 3^6 × 2^6 = (3^3 × 2^3)^2.

Therefore, the prime factorization of 729×64 is: (3^3 × 2^3)^2.