Answer:
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Explanation:
To solve this problem graphically, we will first set up a system of inequalities based on the given information:
x ≥ 8 (Fatoumata must work at least 8 hours lifeguarding)
y ≤ 12 - x (Fatoumata can work at most 12 total hours)
15x + 10y ≥ 140 (Fatoumata must earn a minimum of $140)
To graph these inequalities, we can plot the points (8,0), (12,0), and (0,14) on a coordinate plane and draw lines connecting them. The line between (8,0) and (12,0) represents the constraint on the number of hours Fatoumata can work, while the line between (8,0) and (0,14) represents the constraint on the amount of money she must earn. The shaded region that satisfies all three inequalities is the feasible region.
To find one possible solution, we can pick any point within the feasible region. One such point is (8,6), which represents working 8 hours lifeguarding and 6 hours tutoring. This point satisfies all three inequalities:
x ≥ 8 is true since x = 8
y ≤ 12 - x is true since y = 6 ≤ 12 - 8
15x + 10y ≥ 140 is true since 15(8) + 10(6) = 180 ≥ 140
Therefore, one possible solution is for Fatoumata to work 8 hours lifeguarding and 6 hours tutoring to earn at least $140 while not exceeding 12 total hours worked.