Question

1. Calculate the amount buoyant force that will be

applied to a string of 2 inch OD 1.688 ID open end
tubing when it reaches 7000 ft in a 10700 ft. TVD; 11500
ft. MD well. The density of the working fluid of the well
is 9.6 ppg.
A
B
C
D
10967 lbs
4822 lbs
5183 lbs
3155 lbs

Answer 1

To calculate the buoyant force that will be applied to a string of 2 inch OD 1.688 ID open end tubing, you will need to calculate the weight of the submerged portion of the tubing. This can be done using the following equation:

Weight (lbs) = (Height (ft) * Length (ft) * 0.052 lbs/ft3) * Fluid Density (ppg)

In your scenario, the Height is 10700 ft - 7000 ft = 3700 ft, the Length is 10700 ft, and the Fluid Density is 9.6 ppg.

Therefore, the Weight of the submerged portion of the tubing is:

Weight (lbs) = (3700 ft * 10700 ft * 0.052 lbs/ft3) * 9.6 ppg

Weight (lbs) = 10967 lbs

Now that you know the weight of the submerged portion of the tubing, you can calculate the Buoyant Force by subtracting the Weight of the submerged portion of the tubing from the Weight of the total Height of the tubing. This can be done using the following equation:

Buoyant Force (lbs) = (Height (ft) * Length (ft) * 0.052 lbs/ft3) * Fluid Density (ppg) - Weight (lbs)

Therefore, the Buoyant Force that will be applied to the string of tubing when it