Answer: Area = 113.14 ft sq. Perimeter =
Explanation:
break down the figure and solve area and perimeter for each
triangle = A = 1/2bh
A = 1/2 (8) (6)
A = 24 ft sq.
square = A = LW
A = (8) (8)
A = 64 ft sq
semi circle = A = 1/2 TT r^2
A = 1/2 (3.14) (4)^2
A = 1/2 (3.14) (16)
A = approximately 25.14 ft sq
rounded to hundredths
total AREA = 24 + 64 + 25.14 = 113.14
now we can find perimeter by breaking down the figures again
triangle
we know one leg is 6 ft and the other is 8 ft
we need to find the hypoteneuse using Pythagorean theorem.
a^2 + b^2 = c^2
6^2 = 8^2 = c^2
36 + 64 = c^2
100 = c^2
√100 = √c^2
10 ft = c
square
given two sides are 8ft and 8ft
semi circle - P is the same as circumference
P = ( 1/2 ) 2 π r
P = (1/2) (2) (3.14) (4)
P = 12.56
total PERIMETER = 12.56 + 8 + 8 + 6 + 10 = 44.56 ft
i attached a print screen showing my breakdowns