Question

asked Sep 6, 2024 74.1k views

2 Answers

Ashwin G · Answer 1 · 2024-09-08T03:21:24+0000

We are given that, the measures of sides of blackboard are 5 m 30 cm and 3m 20 cm.

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$\bf \implies5 m + 30 cm \\$

$\sf \implies 5 m + (30)/(100)m \\$

$\sf \implies 5 m + \frac{3\cancel{0}}{10\cancel{0}}m \\$

$\sf \implies 5 m + 0.3 m \\$

$\purple{ \bf \implies 5.3~ m } \\$

$\bf \implies3 m + 20 cm \\$

$\sf \implies 3 m + (20)/(100)m \\$

$\sf \implies 3 m + \frac{2\cancel{0}}{10\cancel{0}}m \\$

$\sf \implies 3 m + 0.2 m \\$

$\purple{\bf \implies 3. 2 ~m} \\$

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$\pink{\frak{\implies Area _((Blackboard) )= Length * Breadth ~m^2}} \\$

$\sf \implies Area _((Blackboard) ) = 5.3 * 3.2 ~m^2 \\$

$\sf \implies Area _((Blackboard) ) = 16.96 m^2 \\$

$\sf \implies 15 * 16.96 \\$

$\pink{\sf \implies Rs ~254.4 } \\$

Sparik · Answer 2 · 2024-09-11T13:50:35+0000

Answer: The cost of painting is Rs.254.4

Explanation:

let l and b be the sides

b=3m 20 cm=3.20m

= 5.30×3.20

=16.96m²

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