Question

Calculate the volume of distilled water that should be added to 25cm³ of a 0.125moldm-³ HCL in order to dilute it 10 times, calculate the volume of the added water

Answer 1

To dilute a solution, you can use the equation (C₁V₁ = C₂V₂), where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume. In this case, you need to add 25 cm³ of distilled water to the 25 cm³ of 0.125 moldm³ HCl solution in order to dilute it 10 times.

Step-by-step explanation:

To calculate the volume of water needed to dilute a solution, you can use the equation (C₁V₁ = C₂V₂), where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume.

In this case, the initial concentration (C₁) of the HCl solution is 0.125 moldm-3 and the initial volume (V₁) is 25 cm³. To dilute it 10 times, the final concentration (C₂) will be 0.125 moldm-3 / 10 = 0.0125 moldm-3. We can substitute these values into the equation to solve for V₂:

(0.125 moldm-3) × (25 cm³) = (0.0125 moldm-3) × (V₂ cm³)

V₂ = (0.125 moldm-3) × (25 cm³) / (0.0125 moldm-3)

V₂ = 25 cm³

Therefore, you need to add 25 cm³ of distilled water to the 25 cm³ of 0.125 moldm-3 HCl solution in order to dilute it 10 times.

Answer 2

Step-by-step explanation:

The volume of distilled water that should be added to 25 cm3 of 0.125 moldm-3 HCl in order to dilute it 10 times can be calculated using the following equation:

Volume of added water = (25 cm3 x 10) / (0.125 moldm-3)

= 200 cm3

Therefore, the volume of distilled water that should be added to 25 cm3 of 0.125 moldm-3 HCl in order to dilute it 10 times is 200 cm3.