Answer: At most 18 acute angles
Explanation:
The sum of the interior angles of an n-sided polygon is (n-2) × 180 degrees. In a convex polygon, each interior angle is less than 180 degrees.
Let a₁, a₂, ..., a₁₁ be the interior angles of the 11-sided polygon. Then the sum of the interior angles is:
a₁ + a₂ + ... + a₁₁ = (11-2) × 180 = 1620 degrees
Since each angle is acute, we know that each angle is less than 90 degrees. Let A be the number of acute angles. Then the sum of the acute angles is at most:
A × 90
So we have:
a₁ + a₂ + ... + a₁₁ ≤ A × 90
Substituting the sum of the interior angles, we get:
1620 ≤ A × 90
Solving for A, we get:
A ≤ 18
Therefore, the polygon can have at most 18 acute angles.