Answer:
900000 joules (J).
Step-by-step explanation:
The work done by a force on an object is given by the product of the force and the displacement of the object in the direction of the force. In this case, the force exerted by the tractor is 600 N, and the displacement of the wagon is 1500 m in the direction of the force.
Therefore, the work done by the tractor on the wagon is:
work = force x displacement x cos(theta)
where theta is the angle between the force and the displacement vectors. Since the force and displacement are in the same direction, theta is 0 degrees, and cos(theta) is equal to 1.
So, the work done by the tractor is:
work = 600 N x 1500 m x 1
= 900000 J
Therefore, the work done by the tractor on the wagon is 900000 joules (J).