Question

6. Deepa's age is three times that of her brother Devan. After 2 years Deepa's age would

be two times that of Devan. How old are they now?

Answer 1

Answer:

Deepa is currently 6 years old
Devan is currently 2 years old.

Step by step explanation:

Let's assume that Devan's current age is x years.

According to the problem, Deepa's age is three times that of Devan's age, which means Deepa's current age is 3x years.

After 2 years,

Devan's age will be x + 2 years,

and

Deepa's age will be 3x + 2 years.

The problem states that Deepa's age after 2 years will be twice Devan's age after 2 years.

So, we can write the equation:

3x + 2 = 2(x + 2)

Solving for x, we get:

3x + 2 = 2x + 4

x = 2

Therefore, Devan's current age is 2 years.

Using this, we can find Deepa's current age, which is three times Devan's age:

Deepa's current age = 3x = 3(2) = 6 years

So, Deepa is currently 6 years old and Devan is currently 2 years old.

Answer 2

Devan's age = 2 years.

Deepa's age = 6 years.

Explanation:

Framing and solving algebraic equation:

Present age:

Let the present age of Devan = x

Present age of Deepa = 3x

After 2 years:

Age of Devan = x + 2

Age of Deepa = 3x + 2

Deepa's age = 2* Devan's age

3x + 2 = 2 *(x + 2)

3x + 2 = 2x + 2*2 {Use distributive property}

3x + 2 = 2x + 4

Subtract '2' from both sides,

3x = 2x + 4 - 2

3x = 2x + 2

Subtract '2x' from both sides,

3x - 2x = 2

x = 2

Devan's age = 2 years.

Deepa's age = 3*2

= 6 years