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Find the area of a semicircle whose diameter is 28cm​

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Answer:

The area of a semicircle with diameter 28 cm is 98π cm², or 307.88 cm² to the nearest tenth.

Explanation:

A semicircle is a two-dimensional shape that is exactly half of a circle.

The area of a circle is given by the formula:


\sf A=\pi r^2

where A is the area of the circle, and r is the radius of the circle.

The diameter of a circle is twice its radius.

Given the diameter of the semicircle is 28 cm, the radius is:


\sf r = (28)/(2) = 14 \; cm

Substituting this into the formula for the area of a circle, we get:


\sf A = \pi(14)^2


\sf A = 196 \pi

Finally, divide this by two to get the area of the semicircle:


\sf Area\;of\;semicircle = (1)/(2) \cdot 196 \pi


\sf Area\;of\;semicircle = 98 \pi\; cm^2

So the area of a semicircle with diameter 28 cm is 98π cm², or 307.88 cm² to the nearest tenth.

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