Answer:
Step-by-step explanation:
We can use the equation for free fall motion to solve this problem:
h = (1/2)gt^2
where:
h = height from which the body started to fall (what we want to find)
g = acceleration due to gravity (9.8 m/s^2)
t = time taken to fall 10 meters (0.2 s)
First, we need to find the velocity of the body when it passes the lower point. Since the body is freely falling, it will have the same velocity as an object thrown vertically downward from rest at the height from which it started to fall (h). We can use the equation for final velocity in free fall to find this velocity:
vf^2 = vi^2 + 2gh
where:
vf = final velocity (which is the velocity when the body passes the lower point)
vi = initial velocity (which is zero)
g = acceleration due to gravity (9.8 m/s^2)
h = height from which the body started to fall (what we want to find)
Rearranging the equation and substituting the known values, we get:
vf = sqrt(2gh)
vf = sqrt(2 × 9.8 m/s^2 × h)
vf = sqrt(19.6h) m/s
Now we can use this velocity to find the time taken by the body to travel the 10-meter distance between the two points:
vf = gt
t = vf/g = sqrt(19.6h)/9.8 s
Finally, we can substitute this value of t into the equation for height and solve for h:
h = (1/2)gt^2 = (1/2) × 9.8 m/s^2 × (sqrt(19.6h)/9.8 s)^2
h = (1/2) × h
h = 5 meters
Therefore, the body started to fall from a height of 5 meters above the higher point.