Answer:
To determine if the solution is saturated or unsaturated, we need to compare the amount of NaCl in the solution to its solubility in water at the given temperature.
The solubility of NaCl in water at room temperature (25°C) is approximately 36 grams per 100 grams of water, or 0.36 g/g. This means that at 25°C, water can dissolve up to 0.36 grams of NaCl per gram of water.
In this case, we have 2.75 grams of NaCl dissolved in 650 grams of water. To find the concentration of NaCl in the solution, we divide the mass of NaCl by the total mass of the solution:
concentration of NaCl = mass of NaCl / total mass of solution
concentration of NaCl = 2.75 g / (2.75 g + 650 g)
concentration of NaCl = 0.0042 g/g
Comparing the concentration of NaCl in the solution to its solubility in water at 25°C, we see that:
0.0042 g/g < 0.36 g/g
Since the concentration of NaCl in the solution is less than its solubility in water, the solution is unsaturated.
Step-by-step explanation: