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How much heat transfer is required to completely boil 1500 g of water (already at its boiling point of 100 C ) into a gas ?

User Habibillah
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Answer:

Step-by-step explanation:

The heat required to completely boil a certain amount of water is given by the formula:

Q = mL

where Q is the heat required, m is the mass of the water, and L is the specific heat of vaporization of water, which is 2260 J/g.

Using the given values:

m = 1500 g

L = 2260 J/g

Substituting these values into the formula, we get:

Q = 1500 g × 2260 J/g

Q = 3,390,000 J

Therefore, 3,390,000 joules of heat transfer is required to completely boil 1500 g of water into a gas.

User Joshua Dyck
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