Answer:
Step-by-step explanation:
The heat required to completely boil a certain amount of water is given by the formula:
Q = mL
where Q is the heat required, m is the mass of the water, and L is the specific heat of vaporization of water, which is 2260 J/g.
Using the given values:
m = 1500 g
L = 2260 J/g
Substituting these values into the formula, we get:
Q = 1500 g × 2260 J/g
Q = 3,390,000 J
Therefore, 3,390,000 joules of heat transfer is required to completely boil 1500 g of water into a gas.