Question

Two forces are applied to a 2. 0 kg block on a frictionless horizontal surface. F1 = 8. ON is applied to the left while F2 = 3. 0 N is applied to the right. What is the

acceleration of the block?



A. ) 2. 5 m/s^2 to the left


B. ) 1. 5 m/s^2 to the right


C. ) 4. 0 m/s^2 to the left


D. ) 2. 5 m/s^2 to the right

Answer 1

The net force acting on the block is the difference between the two forces:

Fnet = F1 - F2 = 8.0 N - 3.0 N = 5.0 N

Using Newton's second law of motion, we can find the acceleration of the block:

Fnet = ma

a = Fnet/m = 5.0 N / 2.0 kg = 2.5 m/s^2

Since the net force is to the left (F1 is greater than F2), the acceleration is also to the left.

Therefore, the correct answer is:

A) 2.5 m/s^2 to the left