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Find the inverse of the function

F(x) = x² + 2x₁ [-1, 00]

User Orangegoat
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To find the inverse of the function F(x) = x² + 2x over the interval [-1, 0], we need to follow these steps:

1. Replace F(x) with y to get y = x² + 2x.
2. Rearrange the equation to isolate x: y = x² + 2x becomes x² + 2x - y = 0.
3. Use the quadratic formula to solve for x in terms of y:

x = (-2 ± sqrt(4 + 4y)) / 2
x = -1 ± sqrt(1 + y)

4. Since the domain of F(x) is [-1, 0], we only consider the negative square root in the expression for x:

x = -1 - sqrt(1 + y)

5. Replace x with its inverse function notation, denoted by F^(-1)(y):

F^(-1)(y) = -1 - sqrt(1 + y)

Therefore, the inverse of the function F(x) = x² + 2x over the interval [-1, 0] is given by F^(-1)(y) = -1 - sqrt(1 + y).
User MonkeyWidget
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