Question

Our fiend is up to his old tricks trying to get his honey from tall tree. If he throws a 5kg rock at 3 m/s at a 15 kg beehive hanging from a branch. When the rock gets stuck in the beehive. how fast withe the beehive fly off the branch? What kind of collision is this?

Answer 1

When the rock gets stuck in the beehive, the two objects are considered to be in an inelastic collision. The beehive will fly off the branch with a velocity of 0.75 m/s. The collision between the rock and the beehive is an inelastic collision.

Step-by-step explanation:

When the rock gets stuck in the beehive, the two objects are considered to be in an inelastic collision. In an inelastic collision, the objects stick together after colliding and move with a common final velocity. To determine the final velocity of the beehive, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.
Before the collision: initial momentum = (mass of rock) x (initial velocity of rock)

= (5 kg)(3 m/s)

= 15 kg·m/s

After the collision: final momentum = (total mass of system) x (final velocity of system)

= (5 kg + 15 kg)(v)

where v is the final velocity of the system.

Equating the initial and final momenta:

15 kg·m/s = (20 kg)(v)

Solving for v:

v = 15 kg·m/s / 20 kg

= 0.75 m/s

Therefore, the beehive will fly off the branch with a velocity of 0.75 m/s.

The collision between the rock and the beehive is an inelastic collision because the two objects stick together after the collision.