1. Not landing on C: 5/6
2. First two letters: 0 (no consecutive A and B)
3. First two letters or vowel: 2/3 (2 A + 2 E / 6 total)
The spinner you sent me appears to have 6 sections labeled A, A, B, E, E, and F.
6. Probability of not landing on C:
There is 1 section labeled C.
There are 6 total sections.
Therefore, the probability of not landing on C is 5 out of 6, or 5/6.
7. Probability of landing on the first two letters of the alphabet:
There are 2 sections labeled A, but they are not consecutive.
Consecutive letters A and B would be required to satisfy this condition.
Therefore, the probability of landing on the first two letters of the alphabet is 0.
8. Probability of landing on the first two letters of the alphabet or a vowel:
There are 2 sections labeled A.
There are 2 sections labeled E (vowels).
There are 6 total sections.
Therefore, the probability of landing on the first two letters of the alphabet or a vowel is (2 A sections + 2 E sections) / 6 total sections = 4/6 = 2/3.