Question

The length of a rectangular poster is 8 more inches than half its width. The area of the poster is 18 square inches. Solve for the dimensions (length and width) of the poster

Answer 1

l = (1/2)w + 8

w((1/2)w + 8) = 18

(1/2)w² + 8w - 18 = 0

w² + 16w - 36 = 0

(w + 18)(w - 2) = 0

w = 2, l = 9

The length of the poster is 9 inches, and the width of the poster is 2 inches.