The length of a rectangular poster is 8 more inches than half its width. The area of the poster is 18 square inches. Solve for the dimensions (length and width) of the poster

Question

asked Sep 12, 2024 124k views

1 Answer

Rpkamp · Answer 1 · 2024-09-18T17:09:29+0000

Answer:

l = (1/2)w + 8

w((1/2)w + 8) = 18

(1/2)w² + 8w - 18 = 0

w² + 16w - 36 = 0

(w + 18)(w - 2) = 0

w = 2, l = 9

The length of the poster is 9 inches, and the width of the poster is 2 inches.