Answer:
There are approximately 3.89 × 10^22 particles in 10.3 grams of TeO2.
Step-by-step explanation:
To determine the number of particles in 10.3 grams of TeO2, we need to use the concept of molar mass and Avogadro's number.
1. Find the molar mass of TeO2:
The molar mass of TeO2 can be calculated by adding up the atomic masses of its constituent elements. Te (tellurium) has a molar mass of 127.6 grams/mol, and O (oxygen) has a molar mass of 16.0 grams/mol. So, the molar mass of TeO2 is:
(1 × molar mass of Te) + (2 × molar mass of O) = (1 × 127.6 g/mol) + (2 × 16.0 g/mol) = 159.6 g/mol.
2. Use the molar mass to find the number of moles:
The number of moles can be calculated by dividing the given mass (10.3 grams) by the molar mass of TeO2 (159.6 g/mol):
Number of moles = 10.3 g / 159.6 g/mol ≈ 0.0645 mol.
3. Use Avogadro's number to find the number of particles:
Avogadro's number, denoted as NA, is approximately 6.022 × 10^23 particles/mol. We can use this number to convert moles to particles. Multiply the number of moles by Avogadro's number to find the number of particles:
Number of particles = 0.0645 mol × (6.022 × 10^23 particles/mol) ≈ 3.89 × 10^22 particles.