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3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O In the above equation, how many moles of water can be made when 13.54 moles of HNO3 are consumed? Round your answer to the nearest tenth.

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Answer:

In the balanced chemical equation:

\[ 3 \text{Cu} + 8\text{HNO}_3 \rightarrow 3\text{Cu(NO}_3)_2 + 2\text{NO} + 4\text{H}_2\text{O} \]

The stoichiometric coefficient of water (H₂O) is 4. This means that for every 8 moles of HNO₃ consumed, 4 moles of water are produced.

Given that 13.54 moles of HNO₃ are consumed, we can set up a ratio to find the moles of water produced:

\[ \text{Moles of water} = \frac{4}{8} \times \text{Moles of HNO}_3 \]

\[ \text{Moles of water} = \frac{1}{2} \times 13.54 \]

\[ \text{Moles of water} = 6.77 \]

Therefore, 6.77 moles of water can be produced when 13.54 moles of HNO₃ are consumed.

Step-by-step explanation:

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