Question

two forces of 11N and 33N are applied to a 22kg box. Find 1) the boxes acceleration when both forces point due east and 2) the boxes acceleration when 11N points due east and 33N points due west.

Answer 1

The acceleration of a 22kg box with forces of 11N and 33N both pointing due east is 2 m/s². When the 11N force points due east and the 33N force points due west, the acceleration is 1 m/s².

Step-by-step explanation:

To find the acceleration of a 22kg box when two forces are applied, we can use Newton's second law of motion which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

1) Both forces point due east:

When the forces of 11N and 33N both point due east, they add together to provide a total force of 44N (11N + 33N). Using the formula a = F/m, we can calculate the acceleration:

a = 44N / 22kg = 2 m/s²

2) 11N force points due east and 33N force points due west:

When the forces are in opposite directions, we subtract the smaller force from the larger one to obtain the net force. In this case, the net force is 22N (33N - 11N). Again using the formula a = F/m:

a = 22N / 22kg = 1 m/s²