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Show that √(5) is irrational
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Aug 8, 2022
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Show
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Mathematics
high-school
Djordje Nedovic
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Djordje Nedovic
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Suppose that √5 = ab where ab is in reduced form. Thus 5 = a2b2 and 5b2 = a2. ... Since there is no integer that is both even and odd, we have reached a contradiction and √5 is irrational.
Kym
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Aug 15, 2022
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