The total resistance of the circuit amounts to 4Ω
How to determine the resistance ?
Firstly, combining 2Ω and 3Ω in series yields an equivalent resistance:
![\[ R_{\text{series}} = 2\Omega + 3\Omega = 5\Omega \]](https://img.qammunity.org/2024/formulas/physics/high-school/19p3opmhoko94yt29rvqfeqa9rfl8ya8in.png)
Subsequently, these resultant 5Ω resistors are arranged in parallel:
![\[ R_{\text{parallel}} = (5\Omega * 5\Omega)/(5\Omega + 5\Omega) = 2.5\Omega \]](https://img.qammunity.org/2024/formulas/physics/high-school/agkabrjez8qh08kqsdbd5rkxwukfo52u9b.png)
Following this, the series combination of 2.15Ω and 1.5Ω leads to:
![\[ R_{\text{AB}} = 2.5\Omega + 1.5\Omega = 4\Omega \]](https://img.qammunity.org/2024/formulas/physics/high-school/4e60psf8x23ysq36pzds00c8eq6vzz1adf.png)
Therefore, the total resistance of the circuit amounts to 4Ω.
Resistance, a foundational concept in physics, quantifies the degree of opposition exhibited by a substance or an electrical component against the passage of an electric current. Denoted by the symbol "R," its measurement is expressed in ohms (Ω).
See missing part of the question on the attached image.