Question

A 0.25 M aqueous solution of potassium chloride, KCl, is tested for conductivity using the type of apparatus shown. What do you predict will happen?

A: The bulb will not light up. KCl is a nonelectrolyte.
B: The bulb will not light up. KCl is in the molecular form when dissolved in water.
C: The light bulb will shine dimly. KCl is only partially ionized in aqueous solution.
D: The light bulb will shine brightly. KCl is highly ionized in aqueous solution.

Answer 1

The light bulb will shine brightly because 0.25 M aqueous KCl solution is highly ionized in water, making KCl a strong electrolyte with high conductivity.

Step-by-step explanation:

When a 0.25 M aqueous solution of potassium chloride (KCl) is tested for conductivity using the type of apparatus shown, one would predict that the light bulb will shine brightly. This is because KCl is a strong electrolyte which is highly ionized in aqueous solution.

When KCl dissolves in water, it separates into potassium ions (K+) and chloride ions (Cl-) which are then free to move and carry electrical current. This high conductivity due to the presence of mobile charged ions allows the light bulb to light up, indicating a completed circuit.