Answer & Explanation:
i) If a student foolishly decides to binge drink 21 beers on their 21st birthday, they would consume a total of 21 x 170 = <<21*170=3570>>3570 calories of digestible energy. Since one calorie is equivalent to raising the temperature of one gram of water by one degree Celsius, and one gallon of water is equivalent to 3,785 grams, the student would have consumed enough energy to raise the temperature of 3,785 grams x 3570 calories = 13,678,950 calories of water from 24 °C to 100 °C. This means that the student could have heated 13,678,950 / 100 = <<136789500/100=136789.5>>136789.5 grams of water from room temperature to boiling, which is equivalent to 136789.5 / 3,785 = <<136789.5/3785=36.19>>36.19 gallons of water.
ii) The energy equivalent of the beer consumed by the student is 3570 calories x 4.184 joules/calorie = 14,889.48 joules. Since one BTU is equivalent to 1,055 joules, this energy is equivalent to 14,889.48 joules / 1,055 joules/BTU = <<14889.48/1055=14.15>>14.15 BTU.
iii) If the student had purchased an equivalent amount of electrical energy from the utility company, they would have to pay 14.15 kW-hr x $0.10/kW-hr = $<<14.15*0.1=1.42>>1.42. This is cheaper than buying beer, as a can of beer typically costs more than $1.42.