Question

A potters wheel moves from rest to an angular speed of 0.20 rev/s in 32.9s.Assuming constant angular acceleration,what is its angular acceleration in rad/s^2? Answer in units of rad/s^2

Answer 1

The angular acceleration of the potters wheel is 0.0121 rad/s^2.

Step-by-step explanation:

The formula to calculate angular acceleration is:

angular acceleration = change in angular velocity / change in time

In this problem, the initial angular velocity is 0 rev/s and the final angular velocity is 0.20 rev/s.

The change in angular velocity is 0.20 - 0 = 0.20 rev/s.

The change in time is 32.9 s.

Converting the angular velocity and time to rad/s, we have:

angular acceleration = (0.20 rev/s - 0 rev/s) / 32.9 s

= 0.20 rev/s * (2π rad/1 rev) / 32.9 s

= 0.0121 rad/s^2

Therefore, the angular acceleration is 0.0121 rad/s^2.