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What is the product of ( 8 – j10 ) and ( 6 + j4) in rectangular form?

a) 48 – j 60
b) 88 – j 28
c) 38 + j 28
d) 48 + j 60​

1 Answer

9 votes

Answer:

b

Explanation:

Given

(8 - j10)(6 + j4) ← expand factors using FOIL

= 48 + j32 - j60 - j²40 [ j² = - 1 ]

= 48 - j28 + 40

= 88 - j28 → b

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