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This is force enacted upon a vehicle moving in a curved path that acts outwardly away from the center of rotation.

User Drekka
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Final answer:

The force described in the question is centrifugal force, a fictitious force experienced while moving on a curved path. The actual force responsible for keeping a vehicle on a curved path is the centripetal force, which must be provided by friction or the normal force on a banked curve.

Step-by-step explanation:

The force enacted upon a vehicle moving in a curved path that acts outwardly away from the center of rotation is known as the centrifugal force. This force is a fictitious force because it does not arise from any physical interaction but from the inertia of the body, as it tries to maintain its straight-line motion due to Newton's first law.

In reality, the actual force that keeps a vehicle turning on a curve is the centripetal force, which acts toward the center of rotation. When a car is on a frictionless banked curve, the net external force (which in the absence of friction is entirely due to the normal force exerted by the surface) must provide the necessary centripetal force, which can be represented as mv²/r, where m is the mass of the vehicle, v is the velocity, and r is the radius of the curve.

For instance, when a car turns on level ground, the friction between the tires and the road provides the centripetal force. If the car is on a banked curve without friction, the normal force of the surface must be adjusted by the angle of the bank to ensure the centripetal force is adequate for the curve.

Without enough friction or an appropriate banking angle, the vehicle would not be able to turn properly and would move in a larger-radius curve or possibly leave the roadway.

User RichK
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