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Construct an isosceles right-angled triangle ∆PQR where ∠

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Answer:

Please find attached the required triangle drawn with Microsoft Visio

Explanation:

The isosceles triangle ΔPQR we are to construct has the following parameters;

∠PQR = 90°

Length of side hypotenuse PR = 4 cm

Therefore, given that the triangle is right triangle is an isosceles triangle the length of each of the side legs are equal

Therefore, we have;

Length of PQ = Length of QR

The length of the legs ,
\overline {PQ} and
\overline {QR}, are given by Pythagoras's theorem as follows;


\overline {PR} = √(
\overline {PQ}² +
\overline {QR}²) = √(
\overline {PQ}² +
\overline {PQ}²) =
\overline {PQ}·√2


\overline {PQ} = 4 cm/(√2) = 2·√2 cm =
\overline {QR}

The required triangle drawn with Microsoft Visio is attached

Construct an isosceles right-angled triangle ∆PQR where ∠-example-1
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