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5. Solve x interims of m and n A.m(x + n) = mn1m = 0 B.n(x-n) = m + x, n = 1​

User Svoisen
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For Equation A: x = 0 for any values of m and n.

For Equation B: there is no solution for x with n = 1.

Solving for x in terms of m and n from the given equations:

Equation A: m(x + n) = mn

We want to isolate x. To do that, we need to get x by itself. Divide both sides by m

(x + n) = n

Subtract n from both sides to isolate x:

x = n - n

x = 0

Therefore, for Equation A, x = 0 regardless of the values of m and n.

Equation B: n(x - n) = m + x, n = 1

Since n = 1 is already given, substitute 1 for n in the equation

1(x - 1) = m + x

Expanding the bracket

x - 1 = m + x

Combining like terms

-1 = m

Since -1 cannot be equal to m, there is no solution for x under Equation B with n = 1.

In conclusion:

For Equation A: x = 0 for any values of m and n.

For Equation B: there is no solution for x with n = 1.

User Nyasia
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