The axis of symmetry of the quadratic equation f(x) = x² - 6x + 5 is x = 3.
The formula for the axis of symmetry for a quadratic equation in standard form f(x) = ax² + bx + c is expressed as:
Axis of symmetry = (-b)/2a
Given the quadratic equation in the question:
f(x) = x² - 6x + 5
Compared to the standard form of a quadratic equation:
a = 1, b = -6 and c = 5
To determine the xis of symmetry, plug the given values into the above formula:
Axis of symmetry = (-b)/2a
Axis of symmetry = (-(-6)) / 2(1)
Simplifying, we get:
Axis of symmetry = 6/2
Axis of symmetry = 6/2
Axis of symmetry, x = 3
Therefore, the axis symmetry is x = 3.