Question

A pipe is closed at one end and the air column vibrate with a fundamental note of 550Hz calculate the length of the resonating air column neglecting end correction

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Answer 1

The length of the resonating air column is 15 cm.

Step-by-step explanation:

Given;

fundamental frequency of the air column, F₀ = 550 Hz

Assume speed of sound in air, v = 330 m/s

The wavelength of the air column is calculated as;

`\lambda = (V)/(F_o) \\\\\lambda = (330)/(550) \\\\\lambda = 0.6 \ m`

The length of the resonating air column is calculated as;

In fundamental mode for closed pipe;

`L = (\lambda )/(4) \\\\L = (0.6)/(4) \\\\L = 0.15 \ m\\\\L = 15 \ cm`

Therefore, the length of the resonating air column is 15 cm.