Answer:
B.
Explanation:
Total coins = 11 ( 3 + 4 + 4 = 11).
The probability of picking a nickel first = 3/11 ( 4 nickels out of 11 total).
The probability of picking a dime second = 4/10 = 2/5 ( 3 dimes out of 10 coins left).
The probability of picking the third coin as a quarter = 4/9 ( 3 quarters out of 9 coins left).
The probability of picking all three in that order = 3/11 x 2/5 x 4/9 = 8/165