Question

suppose the population of a country increases at a steady rate of 3% per year. if the population is 35 million at a certain time, what will it be (in millions) 40 years later? (round your answer to the nearest tenth of a million.)

Answer 1

110 billion or 1.10x10^8 to the nearest 10th.

Explanation:

The population, P, that results from a constant yearly increase from a starting value (S) at a rate (R, as a decimal)) for x years is given by the expression:

P(x) = S*e^(1+R)x

P(40) = (35x10^6)*(1.03)^40

P(40) = (35x10^6)*(1.03)^40

P(40) = (35x10^6)*3.26

P(40) = 1.14x10^8

The popultion will be 114,000,000 [114 billion or 1.14x10^8)

110 billion or 1.10x10^8 to the nearest 10th.