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41 votes
41 votes
2. Determine an equation for a cosine function that has a period of 1800°, an amplitude of 3, a

vertical shaft of 4, and a phase shift of 225° right.

User Eightball
by
3.0k points

1 Answer

19 votes
19 votes

Answer:


y=3cos((1)/(2) (x+}225)+4 phase shift in degrees


y=3cos((1)/(2) (x+(5\pi )/(4)))+4 phase shift in pi radians

Explanation:

Here is the equation for the graph of the cosine function.

y = A sin(B(x + C)) + D

A = amplitude

period is 2π/B

C = phase shift

D = vertical shift

Lets convert 1800° to Pi radians.


1800*(\pi )/(180)


180(10)*(\pi )/(180)


10*(\pi )/(180)


10\pi radians

A = 3

B=2π/ 10π simplifies to
(1)/(2)

C = phase shift

D = 4


y=3cos((1)/(2) (x+}225)+4 phase shift in degrees


y=3cos((1)/(2) (x+(5\pi )/(4)))+4 phase shift in pi radians

User Steve Lazaridis
by
2.8k points
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