Question

In the below figure angle abc is 69 degree, angle acb is 31 degree so find the angle bdc

Answer 1

`\angle BDC=80^(\circ)`

Explanation:

We are given that

`\angle ABC=69^(\circ)`

`\angle ACB=31^(\circ)`

We have to find the angle BDC.

In triangle ABC

Sum of interior angles of triangle=180 degrees

`\angle ABC+\angle ACB+\angle BAC=180^(\circ)`

`69+31+\angle BAC=180`

`100+\angle BAC=180`

`\angle BAC=180-100`

`\angle BAC=80^(\circ)`

`\angle BAC=\angle BDC=80{\circ}`

Angles subtended on the same are ac are equal.

`\angle BDC=80^(\circ)`