Question

What is the output of the following snippet?

def fun(x):
→if x
→→return 1
→else:
→return

print(fun(fun(2)) + 1)

Answer 1

The output of the given snippet is 2.

Step-by-step explanation:

The output of the given snippet is 2.

To understand why, let's break down the code:

1. The function fun(x) takes an argument x.
2. If x is truthy (meaning it evaluates to True), the function returns 1.
3. Otherwise, the function prints 'fun' and returns None.
4. Now, let's evaluate the expression fun(fun(2)) + 1:
5. fun(2) is called first. Since 2 is truthy, the function returns 1.
6. Next, fun(1) is called. Again, 1 is truthy, so the function returns 1.
7. Finally, 1 + 1 is evaluated, resulting in 2.

Therefore, the output of the snippet is 2.